Note. The data given in the table refer to all vehicle variants when unladen.
Instruction. 10 minutes of arc corresponds to a wheel toe of 1.2 mm (for 15" tires).
| Front suspension | Kafer 1200 and 1300 (torsion bar suspension) | Kafer 1302 and 1303 (shock absorber suspension) |
| General convergence of unloaded front wheels | +30°±15’ | +30°+15' |
| Camber front wheels mounted straight | +30°±20' | +1°+20’-40’ |
| Maximum allowable difference between both sides of the vehicle | 30’ | 30' |
| Difference in toe-in when turning the wheel 20°left and right: | ||
| to the left | -1°20’±30’ | - |
| right | -2°10'±30’ | - |
| to chassis N 1142 818 457 | - | -30’±30' |
| from chassis N 1152 000 001 | - | -1°±30’ |
| Longitudinal inclination of an axis of a rotary fist | 3°20’±1’ | 2°+35' |
| corresponds to the difference in toe when turning the wheel 20°to the left and 20°to the right | 2°15'±40’ | 1°20’±25' |
| Maximum allowable difference between the left and right sides of the vehicle | 1° | 1° |
| Rear suspension | Kafer 1200 and 1300 (torsion bar suspension) | Kafer 1302 and 1303 (shock absorber suspension) |
| independent | with diagonal balancer | |
| Camber with normal adjustment after a run of at least 500 km: | ||
| all cars | - | -1°±40’ |
| Kafer 1200 | +1°±1° | - |
| cabriolet | +15'±1' | - |
| Maximum allowable deviation | -1°30' | - |
| Maximum allowable camber difference of both wheels | 20’ | 45’ |
| General convergence at prescribed camber | -5°±10’ | 0°±15’ |
| Maximum permissible deviation in the direction of rotation | Max. 10' | Max. 10' |
Calculation of deviation from the direction of movement
1) For convergence values with the same signs ("+"/"+" or "-"/"-" Subtract the smaller value from the larger one and divide by 2.
Example:
| The amount of convergence of the left rear wheel | The amount of convergence of the right rear wheel |
| +15’ | +5’ |
| 15’-5'= 10’ | |
| 10’:2 = 5’ | |
The deviation from the direction of movement is 5'.
2) Convergence values with different signs ("+"/"-") are summed up and the sum is divided by 2.
Example:
| The amount of convergence of the left rear wheel | The amount of convergence of the right rear wheel |
| +15’ | -5’ |
| 15’+5'=20’ | |
| 20’:2 = 10’ | |
The deviation from the direction of movement is 10'.
The result obtained is the value of the actual deviation of the direction of movement from the longitudinal axis of the vehicle.
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